Black-hole-inspired teleportation reaches high fidelity with no quantum magic

The design is a clean comparison. Both scramblers sit inside the same kind of black-hole-inspired protocol ^[5], and one needs no magic ^[6] while the other typically has substantial amounts ^[7]. If fidelity depended on magic, the Clifford version would fall behind. According to ScienceAlert, the magic-free route still reached high fidelity ^[1].

Magic is the property that lets quantum operations go beyond what an ordinary computer can efficiently simulate ^[2]. A Clifford scrambling step can be simulated efficiently by an ordinary computer, so it cannot supply that beyond-classical capability ^[13]. ScienceAlert notes that magic matters for calculations ordinary computers cannot replicate, though not every quantum task requires it ^[9].

On the idea that this lowers the resource bar: ScienceAlert describes magic as one of quantum computing's more powerful resources ^[10]. A protocol that does without it asks less of the machine doing the scrambling. We think that holds for the scrambling step. The saving in hardware terms is our inference, because the work as described is a mathematical analysis ^[5]. It also assumes the protocol's other ingredients, entanglement and classical communication ^[12], stay the same.

Haar-random scramblers are randomly selected operations ^[7], so any fidelity for them is a figure over a draw of circuits. The account does not include the fidelity value, the number of draws or their spread. A high average can hide a poor draw. Noisy hardware is a separate test.

The motivating physics is still theory. In the picture behind these protocols, information swallowed by one black hole could emerge from another connected to it through a wormhole ^[4]. The protocols themselves use quantum circuits to mimic the scrambling ^[3].